1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vera_Pavlovna [14]
3 years ago
12

Use the ratio table below to determine who the faster swimmer is

Mathematics
2 answers:
ddd [48]3 years ago
4 0
Cant because theres ni ratio
Darina [25.2K]3 years ago
3 0
There is no ratio table attatched so unfortunately cant help, sorry
You might be interested in
Did I do this right? #15 ?
Lelu [443]

Answer:

No you didn't the answer is -6x squared + 15x

Step-by-step explanation:

6 0
3 years ago
The wall of a room are representations of what basic element of geometry
olya-2409 [2.1K]
The wall of a room are representations of what basic element of geometry is “plane”
3 0
3 years ago
Which equation can be used to prove 1 + tan2(x) = sec2(x)?
notsponge [240]

Answer:

fourth option

Step-by-step explanation:

Using the trigonometric identity

cos²x + sin²x = 1

Divide all terms by cos²x

\frac{cos^2x}{cos^2x} + \frac{sin^2x}{cos^2x} = \frac{1}{cos^2x} which gives

1 + tan²x = sec²x

6 0
3 years ago
At a banquet 216 guests sit at 18 tables. Each table has the same number of guests. How many guests per table?
Firdavs [7]
B. 12 guest per table all you need to do it’s divide 216 and 18
3 0
3 years ago
f a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8%, can we use the Normal a
Troyanec [42]

Answer:

Probability of at least 50 obese individuals in our sample is 0.92364 .

Step-by-step explanation:

We are given that a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8% .

Let X = Number of obese individuals

Firstly, X ~ Binom(n=300,p=0.198)

For approximating binomial distribution into normal distribution, firstly we have to calculate \mu and \sigma^{2} .

Mean of Normal distribution, \mu = n * p = 300 * 0.198 = 59.4

Variance of Normal distribution,\sigma^{2} = n * p * (1-p) = 300 *0.198 *0.802 = 47.64

So, now X ~ N(\mu = 59.4 , \sigma^{2} = 47.64)

The standard normal z score distribution is given by;

                     Z = \frac{X-\mu}{\sigma} ~ N(0,1)

So, probability of at least 50 obese individuals in our sample = P(X >= 50)

  P(X >= 50) = P(X > 49.5)  {using continuity correction}

  P(X > 49.5) = P( \frac{X-\mu}{\sigma} > \frac{49.5 - 59.4}{6.9} ) = P(Z > -1.43) = P(Z < 1.43) = 0.92364

Therefore, required probability is 0.92364 .

8 0
3 years ago
Other questions:
  • Brett has a box of sport cards. The box has 12 soccer cards, 15 baseball cards, 5 boxing cards, and 10 basketball cards. What is
    8·1 answer
  • Julia has saved 108 sand dollars and wants to give them away equally to x friends. Write an expression to show how many sand dol
    5·1 answer
  • Hey i need help um pls ill give the crown
    15·2 answers
  • Find the values of a and b
    11·1 answer
  • Can someone please help me on number 5
    12·1 answer
  • What is the product of 2.8 and 2.9? a.) 0.618 b.) 6.18 c.) 9.512 d.) 3.608​
    15·1 answer
  • For questions 9-16 solve the inequality
    9·1 answer
  • 19) You want to solve the system below by eliminating y. You multiply the first equation by 7. By what number should you multipl
    15·1 answer
  • A teacher selects 4 students from her class of 37 to work together on a project. How many ways are there for her to select the s
    6·1 answer
  • What is the answer<br> ????
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!