30-4 (2+5) = 2
30-4(7)=2
30-28=2
Answer:
16
Step-by-step explanation:
The triangle AEC is a right triangle and 2 sides are already filled in.
The hypotenuse is 10 and one side is 6.
So, this is a 3-4-5 right triangle.
Thus, the remaining side EC is 8.
Since EC is congruent to ED, then segment CD is 8+8=16
Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
A. true, the median of a data set is less resistant to outliers than the mean
