Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Correlation Coefficient (r) = 0.989
alph=0.05
Number of observations (n) = 8
determine if there is a linear correlation between chest size and weight.
Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.
What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.
r^2 = square of the correlation Coefficient
r^2 = 0.989^2 = 0.978121
Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
<h3>Discriminant: </h3>
The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.
The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by
<h3> Discriminant Δ = b² - 4ac </h3>
Here we have
x² + 16x + c = 0 equation has only one real solution
Compare given equation with ax²+ bx + c = 0
=> a = 1, and b = 16
As we know when an equation has only one real solution
then its Discriminant will be equal to zero
=> b² - 4ac = 0
By the above values,
=> 16² - 4(1)c = 0
=> 256 - 4c = 0
=> 4c = 256
=> c = 256/4
=> c = 64
Therefore,
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
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Answer: 52.7 Fº
and the 2nd question isn't visible in the photo
Answer:
Raising something to a negative exponent is just taking the reciprocal of the amount.
Step-by-step explanation:
Let's assume that you wanted to know what
is.
To find it, you would take the reciprocal of the x amount. So
becomes
.
This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So
would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase
to
, you would have to multiply a with
two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease
to
, you would have to divide
by a 3 times.
If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times:
means that you are dividing 1 by a 3 times.
Hope this helps.