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lyudmila [28]
3 years ago
7

What is the identity property

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

The identity property shows us that any number that adds zero to itself stays itself. The identity for multiplication tells us that any number multiplied by one is itself.

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En una pasteleria realizan 15 posteles cada 30 min
artcher [175]

Answer:

60

Step-by-step explanation:

había multiplicado 4 y 15 espero que esto ayude

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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
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3 years ago
Sin(2x-pi/2)=sin pi/3
svet-max [94.6K]
This is the answer for your question!

8 0
3 years ago
Which formula represents Charles's law? ?
victus00 [196]

Answer:

The answer would be: V1/T1=V2/T2

7 0
3 years ago
Read 2 more answers
What is the ratio for 8 and 12
Vitek1552 [10]
It can be 8:12 or as a fraction it’s 8/12
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3 years ago
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