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Serggg [28]
3 years ago
12

Quick Start Company makes 12-volt car batteries. After many years of product testing, the company knows that the average life of

a Quick Start battery is normally distributed, with a mean of 43.2 months and a standard deviation of 7.7 months. (a) If Quick Start guarantees a full refund on any battery that fails within the 36-month period after purchase, what percentage of its batteries will the company expect to replace? (Round your answer to two decimal places.)
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

17.11%

Step-by-step explanation:

since 43.2 months is the mean, and the standard deviation is 7.7 months

that means if we take the z score:

z=(36-43.2)/7.7

now that we know how many standard deviations you are away from the mean: -0.9351

using the zscore table you can find the proportion, or you can use the calculator if you have one that can do that.

you get 0.1711 which in percentages is 17.11%

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Whats 80000000000000x200000004500
Sonbull [250]

Answer:

80000000000000x200000004500 =

1.6e+25 which is essentially 1.6 with 25 0's after it

Step-by-step explanation:

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The volume of a cubical bin is 27 cubic feet.
sweet [91]
The answer is the second one. 27=x^3
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if bought 15 caterpillars for $3.00, how much was each caterpillar (find the unit rate for price per caterpillar)
Mashutka [201]

Answer:

20 cents

Step-by-step explanation:

Divide 3 dollars by 15 caterpillars.

3/15 = 0.2

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3 0
2 years ago
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10. A company finds that 45% of first-time visitors to its website do not buy any of its products. If there are 75 first-time vi
vekshin1

Using the binomial distribution, it is found that the probability that exactly 36 of them buy a product is of 0.044.

For each first-time visitor, there are only two possible outcomes, either they buy a product, or they do not. The probability of a first-time visitor buying a product is independent of any other first-time visitor, hence the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 45% of first-time visitors to its website do not buy any of its products, hence 55% buy, that is, p = 0.55.
  • There are 75 first-time visitors on a given day, hence n = 75.

The probability that exactly 36 of them buy a product is P(X = 36), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 36) = C_{75,36}.(0.55)^{36}.(0.45)^{39} = 0.044

More can be learned about the binomial distribution at brainly.com/question/24863377

8 0
2 years ago
Urn 1 contains 3 blue tokens and 2 red tokens; urn 2 contains 2 blue tokens and 4 red tokens. All tokens are indistinguishable.
Dmitry_Shevchenko [17]

Answer:

RR = 0.4

RB = 0.3

BB = 0.22

BR = 0.30

Step-by-step explanation:

P( Urn 1 ) = 2/6 = 1/3

P( Urn 2 ) = 1 - 1/3 = 2/3

Urn 1 contains : 3 blue and 2 red

P( blue | urn 1 ) = 3/5 ( with replacement ) , P( blue | urn 1 ) = 3/4 ( without replacement )

P( red | urn 1 ) = 2 / 5 ( with replacement ) , P(red | urn 1 ) = 1/2 ( without replacement )

Urn 2 contains : 2 blue and 4 red

P ( blue | urn 2 ) = 1/3 ( with replacement ) , P( blue | urn 2 ) = 2/5 ( without replacement )

P ( red | urn 2 ) = 2/3 ( with replacement) , P( red | urn 2 ) = 4/5 ( without replacement )

Determine

<u>i) Possible outcomes when two tokens are drawn from either Urn without replacement </u>

RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4

RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3

BB = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.22

BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30

<u />

8 0
3 years ago
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