Question

What is the equation of the circle with center (4, 4) that passes through the point (10, 14)?

Answer 1

Answer:

Step-by-step explanation:

You use the given information in the standard form of a circle equation to solve for r.  We have (h, k) which is the center and a point (x, y).  The standard equation for a circle is

$(x-h)^2+(y-k)^2=r^2$

Filling in:

$(10-4)^2+(14-4)^2=r^2$ and

$6^2+10^2=r^2$ and

$r^2=136$

Now that we used the coordinate we don't need it anymore.  x and y go back into the equation as x and y, not numbers.  We do, however, need the center.  Writing the equation:

$(x-4)^2+(y-4)^2=136$ which is choice D.