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avanturin [10]
3 years ago
14

(25 pts please help !!)

Mathematics
1 answer:
Sergio [31]3 years ago
7 0

Answer:

1,2, and 4 are all repeating 3 is non repeating

Step-by-step explanation:

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Find the axis of symmetry for this parabola.
Kitty [74]



Find the axis of symmetry for this parabola.

y = 3x2 - 6x - 9

x = -3
☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆x = 1
x = 3
x=4

-b/2a=-(-6)/2(3)
=6/6=1
7 0
3 years ago
Write the equation of the line perpendicular to y= 2/5x+6/6 that passes through the point (-2,6)
Oliga [24]
The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
the line passes through the point (-2,6) so:
6 = (-5/2)×(-2) + b so b = 1


the equation of the line is y = -5/2x +1
3 0
3 years ago
If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

5 0
3 years ago
Does anyone know how to do this?
BlackZzzverrR [31]

Answer:

the 8 means there will be 8 zeros after it so

62.00000000

yw

3 0
3 years ago
A line has a slope of seven and a Y intercept of -10 what is it equation in slope intercept formI want to has a slope of seven a
SOVA2 [1]

Answer:

y=7x-10

Step-by-step explanation:

7 0
3 years ago
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