Question

Write the equation of the line perpendicular to y= 2/5x+6/6 that passes through the point (-2,6)

Answer 1

The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
the line passes through the point (-2,6) so:
6 = (-5/2)×(-2) + b so b = 1


the equation of the line is y = -5/2x +1