X^3 - 5 = -32
x^3 = -32 + 5
x^3 = -27
Now -27 = (-3)^3 so the answer is x = -3
THE ANSWER IS: y=3/2x+1
to find a line that is perpendicular, invert the slope and multiply by -1
so the original slope is -2/3,
invert it to get -3/2 then multiply by -1 to get 3/2
put the given point (-2,-2) and the new slope into point intercept form: y+2=3/2(x+2)
rewrite in standard form to get y=3/2x+1
<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - -
</h3>
➷ The correct answer would be A. which
➶Hope This Helps You!
➶Good Luck :)
➶Have A Great Day ^-^
↬ Hannah ♡
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Find Length of the square :
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Given that the area of the square is 32 cm²:
Area = Length²
![\text {Length =} \sqrt{32}](https://tex.z-dn.net/?f=%5Ctext%20%7BLength%20%3D%7D%20%20%5Csqrt%7B32%7D%20)
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Find Radius :
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Using Pythagorus Theorem to find the radius of the circle:
a² + b² = c²
![( \sqrt{32})^2 + (\frac{ \sqrt{32} }{2} )^2 = ( \text {radius} )^2](https://tex.z-dn.net/?f=%28%20%5Csqrt%7B32%7D%29%5E2%20%2B%20%28%5Cfrac%7B%20%5Csqrt%7B32%7D%20%7D%7B2%7D%20%29%5E2%20%3D%20%28%20%5Ctext%20%7Bradius%7D%20%29%5E2)
![(\text {radius} )^2 = 32 + \dfrac{32}{4}](https://tex.z-dn.net/?f=%28%5Ctext%20%7Bradius%7D%20%29%5E2%20%3D%2032%20%2B%20%5Cdfrac%7B32%7D%7B4%7D%20)
![(\text {radius} )^2 = 40](https://tex.z-dn.net/?f=%28%5Ctext%20%7Bradius%7D%20%29%5E2%20%3D%2040)
![\text { Radius = } \sqrt{ 40 }](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Radius%20%3D%20%7D%20%20%5Csqrt%7B%2040%20%7D%20)
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Find Area of the semi-circle :
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![\text {Area of the semi-circle = } \dfrac{1}{2} \pi r^2](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20the%20semi-circle%20%3D%20%7D%20%20%20%5Cdfrac%7B1%7D%7B2%7D%20%5Cpi%20r%5E2)
![\text {Area of the semi-circle = } \dfrac{1}{2} \pi ( \sqrt{40}) ^2](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20the%20semi-circle%20%3D%20%7D%20%5Cdfrac%7B1%7D%7B2%7D%20%5Cpi%20%28%20%5Csqrt%7B40%7D%29%20%5E2)
![\text {Area of the semi-circle = } 20 \pi](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20the%20semi-circle%20%3D%20%7D%2020%20%5Cpi%20)