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3 years ago

Which of the following is a true polynomial identity?

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

8 0

Answer:

CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC (x^2+1)(x^2+a)-a = x^2(x^2+a+1)

Step-by-step explanation:

I checked the other guys work an it is CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

Ira Lisetskai [31]3 years ago

6 0

Answer:

c. (x^2+1)(x^2+a)-a = x^2(x^2+a+1)

Step-by-step explanation:

You can use FOIL or the distributive property to expand the product of binomials, Then collect terms and factor out the common factor.

(x^2+1)(x^2+a)-a

= x^2(x^2 +a) +1(x^2 +a) -a

= x^4 +ax^2 +x^2 +a -a

= x^4 +ax^2 +x^2

= x^2(x^2 +a +1) . . . . . matches choice C

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Please help with my geometry

erma4kov [3.2K]

25 = hypothenuse
14 = opposite
Use SOHCAHTOA
Give O and H, you can use sin
Sin^-1 = 14/25 = 34.0557
Round to hundreds
Solution: 34.06

8 0

3 years ago

Consider the accompanying matrix as the augmented matrix of a linear system. State in words the next two elementary row operatio

Lubov Fominskaja [6]

Answer:

The answer is below

Step-by-step explanation:

The next step to solve the system, would be to divide the second row by 3 and we would be left with: 3 * R2

[1 -5 3 0 -2

0 1 -7/3 0 4/3

0 0 1 2 -2]

Then what we will do is multiply row 3 by 7/3 and then subtract it from row 2, that is, R2 - 7/3 * R3, and it would look like this:

[1 -5 3 0 -2

0 1 0 14/3 -10/3

0 0 1 2 -2]

And these would be the next two steps in the process of solving the system.

4 0

3 years ago

I need help with all the ones that don't have answers.

zlopas [31]

- What two consecutive odd integers have a sum of 48?

23 + 25 = 48

- Two negative consecutive integers have a sum of -45. What are the integers?

-22 + -23

- The sum of two consecutive integers 75. What are the two integers?

37 + 38 = 75

- What three consecutive odd integers have a sum of 81?

25 + 27 + 29 = 81

Hope I could help! Have a good one. I believe that is all of the unanswered questions. If I missed one, let me know!

7 0

3 years ago

Wen was hiking on a 12-mile route. During the first 2 hours, his hiking speed was 3 mph. During the rest of the hike, his speed

Mars2501 [29]

The total time taken to cover 12 miles distance is 5 hours.

Given the Parameters :

Total distance hiked = 12 miles

Recall :

Distance = speed × time

Let :

Total Time taken = t

We could create an equation thus :

Total distance = 3(2) + 2(t - 2)

12 = 6 + 2t - 4

12 = 2 + 2t

12 - 2 = 2t

10 = 2t

t = 10/2

t = 5

Therefore, the total time taken is 5 hours

Learn more :brainly.com/question/18796573

5 0

2 years ago

Help. Please its urgent show workings.

laiz [17]

Answer:

see explanation

Step-by-step explanation:

There are 2 possible approaches to differentiating these.

Expand the factors and differentiate term by term, or

Use the product rule for differentiation.

I feel they are looking for use of product rule.

Given

y = f(x). g(x) , then

$\frac{dy}{dx}$ = f(x).g'(x) + g(x).f'(x) ← product rule

(a)

y = (2x - 1)(x + 4)²

f(x) = 2x - 1 ⇒ f'(x) = 2

g(x) = (x + 4)²

g'(x) = 2(x + 4) × $\frac{d}{dx}$ (x + 4) ← chain rule

= 2(x + 4) × 1

= 2(x + 4)

Then

$\frac{dy}{dx}$ = (2x - 1). 2(x + 4) + (x + 4)². 2

= 2(2x - 1)(x + 4) + 2(x + 4)² ← factor out 2(x + 4) from each term

= 2(x + 4) (2x - 1 + x + 4)

= 2(x + 4)(3x + 3) ← factor out 3

= 6(x + 4)(x + 1)

--------------------------------------------------------------------------

(b)

y = x(x² - 1)³

f(x) = x ⇒ f'(x) = 1

g(x) = (x² - 1)³

g'(x) = 3(x² - 1)² × $\frac{d}{dx}$ (x² - 1) ← chain rule

= 3(x² - 1)² × 2x

= 6x(x² - 1)²

Then

$\frac{dy}{dx}$ = x. 6x(x² - 1)² + (x² - 1)³. 1

= 6x²(x² - 1)² + (x² - 1)³ ← factor out (x² - 1)²

= (x² - 1)² (6x² + x² - 1)

= (x² - 1)²(7x² - 1)

----------------------------------------------------------------------

(c)

y = (x² - 1)(x³ + 1)

f(x) = x² - 1 ⇒ f'(x) = 2x

g(x) = (x³ + 1) ⇒ g'(x) = 3x²

Then

$\frac{dy}{dx}$ = (x² - 1). 3x² + (x³ + 1), 2x

= 3x²(x² - 1) + 2x(x³ + 1) ← factor out x

= x[3x(x² - 1) + 2(x³ + 1) ]

= x(3x³ - 3x + 2x³ + 2)

= x(5x³ - 3x + 2) ← distribute

= 5 $x^{4}$ - 3x² + 2x

--------------------------------------------------------------------

(d)

y = 3x³(x² + 4)²

f(x) = 3x³ ⇒ f'(x) = 9x²

g(x) = (x² + 4)²

g'(x) = 2(x² + 4) × $\frac{d}{dx}$ (x² + 4) ← chain rule

= 2(x² + 4) × 2x

= 4x(x² + 4)

Then

$\frac{dy}{dx}$ = 3x³. 4x(x² + 4) + (x² + 4)². 9x²

= 12 $x^{4}$ (x² + 4) + 9x²(x² + 4)² ← factor out 3x²(x² + 4)

= 3x²(x² + 4) [ 4x² + 3(x² + 4) ]

= 3x²(x² + 4)(4x² + 3x² + 12)

= 3x²(x² + 4)(7x² + 12)

5 0

2 years ago