Which of the following is a true polynomial identity?

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

8 0

Answer:

CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC (x^2+1)(x^2+a)-a = x^2(x^2+a+1)

Step-by-step explanation:

I checked the other guys work an it is CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

Ira Lisetskai [31]3 years ago

6 0

Answer:

c. (x^2+1)(x^2+a)-a = x^2(x^2+a+1)

Step-by-step explanation:

You can use FOIL or the distributive property to expand the product of binomials, Then collect terms and factor out the common factor.

(x^2+1)(x^2+a)-a

= x^2(x^2 +a) +1(x^2 +a) -a

= x^4 +ax^2 +x^2 +a -a

= x^4 +ax^2 +x^2

= x^2(x^2 +a +1) . . . . . matches choice C

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mariarad [96]

Answer:

Step-by-step explanation:

Once

$\sqrt{xy} = 6$

We know that $xy = 36$

There are infinity values for $x, y$ , but considering $x, y \in \mathbb{Z}$

Below we have all the solutions for $x, y$

Negative:

$\\x = -36 \text{ and } y = -1\\x = -18 \text{ and } y = -2\\x = -12 \text{ and } y = -3\\x = -9 \text{ and } y = -4\\x = -6 \text{ and } y = -6\\x = -4 \text{ and } y = -9\\x = -3 \text{ and } y = -12\\x = -2 \text{ and } y = -18\\x = -1 \text{ and } y = -36\\$

Positives:

$x = 36 \text{ and } y = 1\\x = 18 \text{ and } y = 2\\x = 12 \text{ and } y = 3\\x = 9 \text{ and } y = 4\\x = 6 \text{ and } y = 6\\x = 4 \text{ and } y = 9\\x = 3 \text{ and } y = 12\\x = 2 \text{ and } y = 18\\x = 1 \text{ and } y = 36\\$