Answer:
The value of pressure at an altitude of 10000 ft = 10 
Step-by-step explanation:
Given data
Atmospheric pressure 
= 14.7
Pressure at 4000 ft = 12.6
If temperature is constant then the atmospheric pressure is varies with the altitude according to law
P (h) = 
------ (1)
where k= constant & h = height
12.6 = 14.7 
0.857 =
㏑ 0.857 = - 4000 k
-0.154 = - 4000 k
k = 3.85 × 
Thus the atmospheric pressure at an altitude of 10,000 ft is
14.7 × ----- (2)
Product of k & h is
k h = 3.85 × × 10000
k h = 0.385
Put his value of k h = 0.385 in equation (2) we get
14.7 × 
10
This is the value of pressure at an altitude of 10000 ft.
Answer:
a : b = 25 : 9
Step-by-step explanation:
(3a - 5b) : (3a + 5b) = 1 : 4
Product of extremes = product of means
(3a - 5b) *4 = (3a +5b) * 1 {Distributive property}
3a * 4 - 5b*4 = 3a + 5b
12a - 20b = 3a + 5b
Add 20b to both sides
12a = 3a + 5b + 20b
12a = 3a + 25b
Subtract 3a from both sides
12a - 3a = 25b
9a = 25b
a:b = 25 : 9
Answer:
B. 105
Step-by-step explanation:
To write a ratio as a fraction, we simply take the first number in the ratio and make it the numerator while taking the second number in the ratio and making it the denominator.
Because we want the ratio of engines to box cars, our ratio should be:
number of engines/number of box cars
When we substitute in our respective values, we get:
4/18
To simplify this ratio, we have to find the GCF, or greatest common factor of the numerator and the denominator, which in this case is 2. To simplify, we divide both the numerator and the denominator by the GCF, as follows:
4/2 / 18/2
When we simplify, we get:
2/9
Therefore, your answer is 2/9.
Hope this helps!
