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3 years ago

Find 3 pairs that satisfy the function: y = -2x

Mathematics

1 answer:

KengaRu [80]3 years ago

8 0

Answer:

(-1,0) (-2, 4)( -3,6) -4,8)Step-by-step explanation:

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I need help plzzzzzzz

NeTakaya

The fourth one or the second one on the bottom

5 0

3 years ago

Determine the zeros of the function <br> 5) y=-x² + 2x + 1

Rus_ich [418]

<h3>Zeros of function are $x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}$ </h3>

<em><u>Solution:</u></em>

<em><u>We have to find the zeros of the function</u></em>

$y = -x^2 + 2x+1$

Find the zeros of function:

$-x^2 + 2x+1 = 0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-1,\:b=2,\:c=1\\\\x =\frac{-2\pm \sqrt{2^2-4\left(-1\right)1}}{2\left(-1\right)}$

$Simplify\\\\x=\frac{-2 \pm \sqrt{4+4}}{-2}\\\\x =\frac{-2 \pm \sqrt{8}}{-2}\\\\Simplify\\\\x =\frac{-2 \pm 2 \sqrt{2}}{-2}\\\\x = 1 \pm \sqrt{2}$

We have two zeros

$x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}$

Thus zeros of function are $x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}$

3 0

3 years ago

Read 2 more answers

Position vectors m and n have terminal points of (2, ) and (1, y), respectively.

OLEGan [10]

This problem involves the dot product.

You must provide all info for position vector m. Your (2,) is inadequate.

Supposing that the terminal point of vector m were (2,3), then

m dot n would equal 8, or 8 = 2*2+3*y. Then 8 = 4 + 3y, and 4 = 3y, and y =3/4.

Please type in the terminal point of vector m and then answer this question following the above example.

7 0

3 years ago

The highest temperature ever recorded in Death Valley, California, was 121°, while the lowest ever recorded there was 13° below

s344n2d4d5 [400]

Answer:

The answer is C

Step-by-step explanation:

Remember it says 13' below zero, and 121' is the highest temperature.

7 0

3 years ago

Read 2 more answers

Look at this equation. 3(x + 1) = 3x + Which number can be placed in the box that would create an equation that has an infinite

luda_lava [24]

Your final equation would be 3(x+1)= 3x+3 because if you do 3 times x you get 3x so if you do 3 times 1 you get 3 making the equation have infinite solutions.

The final answer is: 3(x+1)= 3x+3 for an infinite number of solutions.

3 0

3 years ago