Answer:
31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation ![s = \sqrt{\frac{p(1-p)}{n}}](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
In this question, we have that:
![\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2](https://tex.z-dn.net/?f=%5Cmu%20%3D%20270%2C%20%5Csigma%20%3D%2090%2C%20n%20%3D%2018%2C%20s%20%3D%20%5Cfrac%7B90%7D%7B%5Csqrt%7B18%7D%7D%20%3D%2021.2)
What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?
This is the pvalue of Z when
. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
By the Central Limit Theorem
![Z = \frac{X - \mu}{s}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7Bs%7D)
![Z = \frac{260 - 270}{21.2}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B260%20-%20270%7D%7B21.2%7D)
![Z = -0.47](https://tex.z-dn.net/?f=Z%20%3D%20-0.47)
has a pvalue of 0.3192.
31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days