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frez [133]
3 years ago
12

Someone help meee pleaseee

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0
Length×base×height
1.5×0.4×3
1.8 meter cube
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7/5 x 7/1 = 49/5 or 9 4/5
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Relay races called for 8 people on a team. There were 43 men and 34 women who wanted to race. How many teams could be formed ?ho
ELEN [110]

It would be an odd number of teams. What I did was add 43 and 34 together. Which gave me 77. So 77 people total wanted to race. There can only be 8 racers on each team. Each means to divide.  So I divided 8 and 77. It gave me 9 with a remainder of 5. So there will e 9 teams and 5 racers left out. (:

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A student's course grade is based on one midterm that counts as 15% of his final grade, one class project that counts as 15% of
kow [346]

Answer:

Overall final score = 77.75% ; Grade = C.

Step-by-step explanation:

The approach to solve this question is to realize that the marks have to be converted into the respective percentages of the whole course. This means that the marks of all the components have to be normalized according to the grading breakdown.

Project Marks = 97/100. Weightage = 15%. So 97*15/100 = 14.55/15.

This means that the student received 14.55 marks in the project out of 15.

Similarly for other components:

Mid-Term Marks = 83/100. Weightage = 15%. So 83*15/100 = 12.45/15.

Homework Marks = 82/100. Weightage = 35%. So 82*35/100 = 28.7/35.

Finals Marks = 63/100. Weightage = 35%. So 63*35/100 = 22.05/35.

After the conversion process, add up the normalized marks, which are now acting as the percentages earned in all the components.

Aggregate Percentage = 14.55 + 12.45 + 28.7 + 22.05 = 77.75%.

According to the grade scale, the student receives a C because 70 is less than 77.75 and 77.75 is less than 80.

Summarizing, the student receives a C at 77.75%!!!

7 0
4 years ago
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