We know that
if the club includes one set of identical
triplets wearing matching clothes
then
the number of different arrangements that are
possible is
10! / 3! = (10*9*8*7*6*5*4*3!)/3!
=604,800
The answer is
<span>604,800</span>
Answer:
Because the hypotenuse might not be a perfect square
Step-by-step explanation:
First, you plot the coordinates to visualize the problem clearly. As you can see in the picture, the longest sides could either be one of those marked in red. This could be initially determined when you use visual estimation. We measure this using the distance formula: d = √[(x2-x1)^2 + (y2-y1)^2)]
Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units
Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units
They are of equal length. Both are the longest sides which measures
4.24 units.
Answer: what are you talking about????????
Step-by-step explanation:
X+y=156
<span>0.05x+0.25y=21.6
-1/4*/ x+y=156
1/20x+1/4y=216/10
-1/4x-1/4y=156*-1/4=-39
</span>1/20x+1/4y=216/10
<span>+--------------------------
-4/20x=-17,4
x=87
</span>x+y=156
<span>
87+y=156 y=69
this question answer is </span><span>87 nickels and 69 quarters</span><span>
</span>