I do not think there are any. If you used -20 and 2, which would be close to 16, the sum would be 18.
Honestly I think you are correct, not trying to take your point. :)
F '(x<span>) = </span>2(3x2<span> + 5) + 6x(</span>2x<span> - </span>1<span>) ... + </span>3), s(x<span>) = </span>x<span> - 4. Use the </span>product<span> rule table. below to get: r'(</span>x) = 20x + 11. s'(x<span>) = </span>1<span> ... f'(</span>x) = (x<span> - 4</span>)(20x + 11) - (5x<span> - </span>2)(2x<span> + </span>3)/(x<span> - 4)</span>2<span>.</span>First, we will distribute 2x<span> to (</span>x<span> + 5), then we will distribute </span>3<span>. ... </span>5x<span>. That is,. multiplying binomials. 6x − </span>x<span>= </span>5x<span>. Example </span>2<span>. Multiply (3x − </span>1)(x<span> + </span>2). Answer. 3x2<span> + </span>5x<span>
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Step-by-step explanation:
hope this will help you mark me as brinalist friend please
