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BabaBlast [244]
3 years ago
5

This is the math problem 150-4[3+9/4-1•(14-11) to the 2nd power]

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0
150-4[3+9/4-1*(14-11)^2]
150-4[12/3*(3)^2]
150-4[4*3^2]
150-4[4*9]
150-4*36
150-144
6
(I think)
poizon [28]3 years ago
6 0

Answer:

Final result :

 165

Step by step solution :

Step  1  :

Equation at the end of step  1  :

            9

 150-(4•((3+—)-(1•32)))

            4

Step  2  :

           9

Simplify   —

           4

Equation at the end of step  2  :

                    9    

 150 -  (4 • ((3 +  —) -  32))

                    4    

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  4  as the denominator :

         3     3 • 4

    3 =  —  =  —————

         1       4  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 4 + 9     21

—————————  =  ——

    4         4

Equation at the end of step  3  :

              21    

 150 -  (4 • (—— -  32))

              4    

Step  4  :

Rewriting the whole as an Equivalent Fraction :

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  4  as the denominator :

         32     32 • 4

   32 =  ——  =  ——————

         1        4  

Adding fractions that have a common denominator :

4.2       Adding up the two equivalent fractions

21 - (32 • 4)     -15

—————————————  =  ———

      4            4

Equation at the end of step  4  :

             -15

 150 -  (4 • ———)

              4

Step  5  :

Final result :

 165

Processing ends successfullyFinal result :

 165

Step by step solution :

Step  1  :

Equation at the end of step  1  :

            9

 150-(4•((3+—)-(1•32)))

            4

Step  2  :

           9

Simplify   —

           4

Equation at the end of step  2  :

                    9    

 150 -  (4 • ((3 +  —) -  32))

                    4    

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  4  as the denominator :

         3     3 • 4

    3 =  —  =  —————

         1       4  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 4 + 9     21

—————————  =  ——

    4         4

Equation at the end of step  3  :

              21    

 150 -  (4 • (—— -  32))

              4    

Step  4  :

Rewriting the whole as an Equivalent Fraction :

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  4  as the denominator :

         32     32 • 4

   32 =  ——  =  ——————

         1        4  

Adding fractions that have a common denominator :

4.2       Adding up the two equivalent fractions

21 - (32 • 4)     -15

—————————————  =  ———

      4            4

Equation at the end of step  4  :

             -15

 150 -  (4 • ———)

              4

Step  5  :

Final result :

 165

Processing ends successfully

Step-by-step explanation:

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