How do you write -x+3y=6 in slope intercept form?

Mathematics

2 answers:

Afina-wow [57]3 years ago

8 0

Commenter jdoe said it right: solve for y and leave the rest on the other side.

-x + 3y = 6

3y = 6 + x add x on both sides

3y = x + 6 rearrange to get the x first

y = (x + 6) /3 divide both sides by 3

y = x/3 + 6/3 split the numerator (caution - never split denominators)

y = x/3 + 2 simplify 6/3

Thus the line in slope intercept form of y = mx + b is y = $y = \frac{1}{3} x + 2$

mafiozo [28]3 years ago

4 0

Given -x+3y=6, solve for y:

Adding x to both sides, we get:

3y = x + 6

Dividing both sides by 3, we get:

y = (1/3)x + 2. The slope of this line is 1/3 and the y-intercept is 2.

You might be interested in

F(x)=x^2+10x-12

weqwewe [10]

Answer:

Therefore the two values required are 2.08 and -11.08.

Step-by-step explanation:

i) f(x) = $x^{2}$ + 10x - 12 is a quadratic equation and a quadratic equation will have two roots whose values when substituted in to the given quadratic equation will give the value.

ii) The question is therefore essentially asking us to find the roots of the given quadratic equation.

This can be done by equating the given quadratic equation to zero and then solving the equation for its roots.

∴ $x^{2}$ + 10x -12 = 0 ⇒ x = (-10 ± $\sqrt{10^{2} +(48)}$ ) ÷ 2

= (-10 ± 12.166)÷2 = 2.08, -11.08

Therefore the two values required are 2.08 and -11.08

3 0

3 years ago

Please help me solve

arsen [322]

Answer:

18 square centimeters

Step-by-step explanation:

Notice that if e is the midpoint of the side CB, and angle $\angle x = 45^o$ , then this rectangle is in fact two squares of side 3 cm put together. therefore, side CD has a length of 6 cm, and as a result, the area of the figure is given by the product base times height = 6 x 3 = 18 $cm^2$