Question

How do you write -x+3y=6 in slope intercept form?

Answer 1

Commenter jdoe said it right: solve for y and leave the rest on the other side.

-x + 3y = 6

3y = 6 + x add x on both sides

3y = x + 6 rearrange to get the x first

y = (x + 6) /3 divide both sides by 3

y = x/3 + 6/3 split the numerator (caution - never split denominators)

y = x/3 + 2 simplify 6/3

Thus the line in slope intercept form of y = mx + b is y = $y = \frac{1}{3} x + 2$

Answer 2

Given -x+3y=6, solve for y:

Adding x to both sides, we get:

3y = x + 6

Dividing both sides by 3, we get:

y = (1/3)x + 2. The slope of this line is 1/3 and the y-intercept is 2.