∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
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Answer:
No
Step-by-step explanation:
The equation of a circle with center (a,b) and radius r is given as:

If a given point (x,y) does not lie on this circle, it will not satisfy its equation.
This means the distance from the point to the center is not equal to the radius.
It is either less or greater than the radius.
Hence you cannot write the equation of the circle.
Answer:
y= -3x +10
the y-intercept is at 10 and then go 3 down one to the right
Step-by-step explanation:
Answer:
C. 40 square inches but i could be wrong