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ser-zykov [4K]
3 years ago
14

The data in the table represent the height of an object over

Mathematics
2 answers:
Arada [10]3 years ago
5 0

<u>Answer:</u>

The correct answer option is quadratic, because the height increases and then decreases.

<u>Step-by-step explanation:</u>

We are given the following data in the table which represents the height of an object over  time:

Time (s)          Height (ft)

     0                      5

      1                     50

     2                     70

     3                     48

We know that in situation where the values increase and then decreases, a quadratic model is used.

From the values given in the table, we can see that the values of height first increased and then decreased with the increase in time.

Therefore, the model used is quadratic, because the height increases and then decreases.

DENIUS [597]3 years ago
5 0

Answer:

<h2>B</h2>

Step-by-step explanation:

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julsineya [31]

Answer: C

Step-by-step explanation:

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X + 8 = 0

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If -8 is substituted into f(x), the equation will tend to zero. That is,

F( -8 ) = 0

C is therefore the correct answer.

4 0
4 years ago
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Slav-nsk [51]

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find out how many units higher g(x) is compared to f(x).

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Step-by-step explanation:

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3 years ago
Identify the rational numbers as positive or negetive -1/-7
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8 0
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A fish tank holds 25 gallons of water. How many quarts of water does the fish tank hold?
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Step-by-step explanation:

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3 0
2 years ago
Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)​
umka2103 [35]

Answer:

<u>GIVEN :-</u>

  • ∠A = 15°
  • Length of AB (hypotenuse) = 60 ft

<u>TO FIND :-</u>

  • Length of BC
  • Length of AC
  • Area of ΔABC

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}

<u>SOLUTION :-</u>

In ΔABC ,

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=> 0.2588... = \frac{BC}{60}

=> BC = (0.2588....) \times 60 = 15.5291..... ≈ 15.5 ft

  • \cos 15 = \frac{AC}{60}

=> 0.9659..... = \frac{AC}{60}

=> AC = (0.9659.....) \times 60 = 57.9555..... ≈ 58 ft

Area of ΔABC = \frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2

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