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ser-zykov [4K]
3 years ago
14

The data in the table represent the height of an object over

Mathematics
2 answers:
Arada [10]3 years ago
5 0

<u>Answer:</u>

The correct answer option is quadratic, because the height increases and then decreases.

<u>Step-by-step explanation:</u>

We are given the following data in the table which represents the height of an object over  time:

Time (s)          Height (ft)

     0                      5

      1                     50

     2                     70

     3                     48

We know that in situation where the values increase and then decreases, a quadratic model is used.

From the values given in the table, we can see that the values of height first increased and then decreased with the increase in time.

Therefore, the model used is quadratic, because the height increases and then decreases.

DENIUS [597]3 years ago
5 0

Answer:

<h2>B</h2>

Step-by-step explanation:

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Danny charges $40 for 4 hours of swimming lessons, Martin charges $85 for 5 hours of swimming lessons. Who offers a better deal?
Ratling [72]

Answer:

Danny does

Step-by-step explanation: 40 / 4 = 10

                                              85 / 5 = 17

10 is less than 17 meaning that Danny is offering a better deal.

Hope this helps!

4 0
3 years ago
Read 2 more answers
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
A chemist is using 356 milliliters of a solution of acid and water. If 14.1% of the solution is acid, how many milliliters of ac
likoan [24]
50.2 milliliters of acid
4 0
3 years ago
1.A bag has 4 green blocks, 3 red blocks, 2 blue blocks, and 1 yellow block. Find the probability of randomly selecting a block
maks197457 [2]

Answer: 1) 7/10  2) 15  3) 240  4) 1/4  5) 4/9  6) 1/20  7) No, not independent

Step-by-step explanation:

1. 4 green+3red+2blue+1yellow = 10 total

if 3/10 are red, then 7/10 are not red. So the second option, 7/10

2. 3 cartons in every 40

40*5 = 200

so do 3*5 = 15

so 15 or the third option

3. 40 out of 110

110*6 = 660

so do 40*6 = 240

so 240 or the fourth option

4.

Flipping heads: 1/2

rolling even: well, there is 2, 4, and 6, or 3 even numbers so 3/6 or 1/2

do 1/2*1/2 = 1/4

so 1/4 or the third option

5. Numbers more than 2: 3, 4, 5, 6 (4 numbers)

4/6 or 2/3 chance the first time, 2/3 chance the second time

do 2/3*2/3 = 4/9

so 4/9 or the second option

6. 5 dishes and 4 desserts

1/5 chance of picking the dish

1/4 chance of picking the dessert

do 1/5*1/4 = 1/20

so 1/20 or the fourth option

7. Since you don’t replace the marble after picking it, it affects the outcome of the second draw. Therefore the events are dependent, or not independent. So the second option.

7 0
3 years ago
The value of which of these expressions is closest to e?
Anna [14]

Answer:

Using a calculator, we can check that e=2.718281828.

Step-by-step explanation:

Lets evaluate each one of our expression the check which one is closest to e:

(1+ \frac{1}{31} )^{31}=2.675686306

(1+ \frac{1}{32})^{32}=2.676990129  

(1+ \frac{1}{34} )^{34}=2.679355428

(1+ \frac{1}{33} )^{33}=2.678207651

We can conclude that the value of (1 +1/34) to the power of 34 is the closest to the value of e.

4 0
3 years ago
Read 2 more answers
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