Find the measure of AB

Mathematics

1 answer:

Sidana [21]2 years ago

8 0

Answer:

AB = 7

Step-by-step explanation:

When 2 secants intersect a circle from an external point, then

CB × CA = CD × CE, that is

5(5 - 4 + x) = 6(6 + 4) ← simplify left side

5(1 + x) = 6 × 10 ← distribute left side

5 + 5x = 60 ( subtract 5 from both sides )

5x = 55 ( divide both sides by 5 )

x = 11

Hence

AB = - 4 + x = - 4 + 11 = 7

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Plz help me solve this ASAP and show the work thank you

Vinil7 [7]

Answer:

Step-by-step explanation:

The diagram is right angle triangle so we can use SOHCAHTOA

So in the diagram we have 62 degree opposite to x and the hypotenuse

Step 1

Sin62=x/16

Step 2

X=16sin62 by cross multiplication

Step 3

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X=14

6 0

2 years ago

Need help with this im confused

Jet001 [13]

Answer:

$-\frac34 -\frac14 i$

Step-by-step explanation:

Let's start with distributing: $\frac1{4i}-\frac{3i}{4i}$ Simplify i with i in the second term, and rearrange. $-\frac34 +\frac1{4i}$ . Since i in the denominator looks ugly, let's multiply top and bottom by i. $-\frac34 +\frac i{4i^2} = -\frac34 +\frac i{4(-1)} =-\frac34 -\frac14 i$ . The middle passage is based on the fact that, by definition, $i^2=-1$