Question

Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?

Answer 1

Move the decimal point over to the left 2 spaces and mult by the number of ml .
473 ml times 0.70 = 331.1 ml

Answer 2

Hello!

Rubbing alcohol is 70.0% isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a full 1 pint (473 ml) container?

We have the following information:  

% V/V (percentage of volume per volume) = 70  

V1 (solute volume) = ? (in mL)  

V (volume of the solution) = 473 mL

We apply the data to the formula of volume percentage of the solute per volume of solution, we will have:  

$\%\:v/v = \dfrac{v_1}{v} *100$

$70 = \dfrac{v_1}{473}*100$

$70*473 = 100*v_1$

$33110 = 100\:v_1$

$100\:v_1 = 33110$

$v_1 = \dfrac{3311\diagup\!\!\!\!0}{10\diagup\!\!\!\!0}$

$\boxed{\boxed{v_1 = 331.1\:mL\:of\:isopropyl\:alcohol}}\Longleftarrow(solute\:volume)\:\:\:\:\:\:\bf\purple{\checkmark}$

Answer:

331.1 ml of isopropyl alcohol

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