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Answer:
The concentration of KOH is 0.186 M
Explanation:
First things first, we need too write out the balanced equation between HBr and KOH.
This is given as;
KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)
From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.
We use the acid base formular in calculating unknown concentrations. This is given as;
where;
Ca = Concentration of acid
Va = Volume of acid
Cb = Concentration of base
Vb = Volume of base
na = Number of moles of acid
nb = Number of moles of base
KOH is the base and HBr is acid.
Hence;
Ca = 0.225
Va = 35
Cb = ?
Vb = 42.3
na = 1
nb = 1
Making Cb subject of formular we have;
Cb = (0.225 * 35 * 1) / (42.3 * 1)
Cb = 0.186 M
<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.
<u>Explanation:</u>
We are given:
Initial pressure of air = 769.0 torr
Final pressure of air = 717.1 torr
Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr
To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 51.9 torr
V = Volume of the gas = 2.20 L
T = Temperature of the gas = 292 K
R = Gas constant =
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
To calculate the mass from given number of moles, we use the equation:
Moles of oxygen gas = 0.0063 moles
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.