Answer: 6.3 x 10^-3 moles
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
So, 1 mole of potassium = 6.02 x 10^23 atoms
Z moles = 3.78 x 10^21 atoms
To get the value of Z, we cross multiply:
(3.78 x 10^21 atoms x 1mole) = (6.02 x 10^23 atoms x Z moles)
3.78 x 10^21 = (6.02 x 10^23 x Z)
Z = (3.78 x 10^21) ➗ (6.02 x 10^23)
Z = 0.63 x 10^-2)
Place the result in standard form
Hence, Z = 6.3 x 10^-3 moles
Thus, there are 6.3 x 10^-3 moles of potassium in 3.78 x 10^21 atoms of K.
<h3>
Answer:</h3>
1170.43 m³
<h3>
Explanation:</h3>
<u>We are given;</u>
- Initial pressure, P1 as 808 kPa
- Initial temperature, T1 as 585 K
- Initial volume, V1 as 295 m³
- New pressure, P2 as 102 kPa
- New temperature, T2 as 293 K
We are required to find the new volume;
- We are going to use the combined gas law
- According to the gas law;
- Thus, rearranging the formula;
Therefore, the volume is 1170.43 m³
Answer:
.46 moles H2O2
3,014 grams Au
Explanation:
H2O2:
15.78g (1 mol/34g) = .46 moles H2O2
Au:
15.3mol (197g/mol) = 3,014 grams Au
Answer:
compaction and cementation
I love science by the way
