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vitfil [10]
3 years ago
8

Is (NH4)2 a ionic compound

Chemistry
1 answer:
nikitadnepr [17]3 years ago
5 0
No it's not. It has covalent bonds because the elements are both non-metals.
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1. Nene geese in Hawaii are endangered because of
lesya692 [45]

Answer:

✔ habitat destruction

Explanation:

the 3 reasons are:

hunting

habitat loss

introduced predators

summed up its habitat destruction

8 0
2 years ago
State the type of bonding—ionic, covalent, or metallic—you would expect in each: (c) Na(s).
miv72 [106K]

Na(s) forms an ionic bond.

<h3>What is ionic bond?</h3>

The main interaction in ionic compounds is ionic bonding, a type of chemical bonding that involves the electrostatic attraction between two atoms or ions with dramatically differing electronegativities. Along with metallic and covalent bonds, it is one of the most common types of bonds. Atoms (or collections of atoms) possessing an electrical charge are known as ions. Ions with negative charges are created when atoms gain electrons (called anions). Positively charged ions are produced when atoms lose electrons (called cations). In contrast to covalence, this electron transfer is referred to as electrovalence.

Ionic chemicals normally do not conduct electricity when solid, only when molten or in solution. Depending on the charge of the ions they are made of, ionic compounds typically have a high melting point.

To learn more about ionic bond from the given link:

brainly.com/question/13526463

#SPJ4

5 0
1 year ago
The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass to 1 decimal place.
xxMikexx [17]

Answer:

answer-

The relative atomic mass = 204.4

explanation:

Thallium -203 = 30%

Thallium -205 = 70%

Therefore ,

relative mass of thallium = (30×203 + 70×205)/100

relative mass of thallium = (20440)/100

relative mass of thallium = 204.40 amu

Thus,

relative atomic mass of thalium =204.4 ( to 1 decimal place)

6 0
3 years ago
Select the situation below that would produce a total displacement of zero
likoan [24]

Answer:

uhhhhhjjj??????????

6 0
3 years ago
Read 2 more answers
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
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