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MrRa [10]
3 years ago
7

A solution is made by mixing 34.5 g of sugar with 75.0 g of water. What is the mass percent of sugar in this solution?

Chemistry
1 answer:
lubasha [3.4K]3 years ago
5 0

the mass percent of sugar in this solution is 46%.

Answer:

Solution given:

mass of solute=34.5g

mass of solvent=75g

mass percent=\frac{mass\:of\:solute}{mass\:of \:solvent}*100\%

=\bold{\frac{34.5}{75.0}*100\%=46\%}

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mars1129 [50]
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3 years ago
Which statement accurately describes non renewable energy sources ?
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a resource that cannot be replenished in a short period of time

5 0
3 years ago
Read 2 more answers
14 km is how many centimeters?
Yuki888 [10]

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8 0
3 years ago
An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

Volume= 236 mL x (\frac{1 L}{1000 mL}) = .236 L

Pressure= 740 mm Hg x (\frac{1 atm}{760 mm Hg})= 0.97 atm

Temperature= 22C + 273= 295 K

mass= 0.443 g

Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

MM= 49.2 g/mol

3 0
3 years ago
2 icl + h2i2 + 2 hcl is first order in icl and second order in h2. Complete the rate law for this reaction in the box below. Use
OleMash [197]

2 ICl + H2   ----> I2 + 2 HCl

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[ICl] = 0.273 m and [H2] = 0.217 m

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5 0
3 years ago
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