Question

Please help! Which expression is equal to..?

Answer 1

Answer:

A

Step-by-step explanation:

Before we can add the 2 fractions we require them to have a common denominator.

Multiply the numerator/ denominator of the first fraction by x

Multiply the numerator/ denominator of the second fraction by (x + 3)

= $\frac{3x(x)}{x(x+3)}$ + $\frac{(x-2)(x+3)}{x(x+3)}$

Now simplify the numerator, leaving the denominator

= $\frac{3x^2+x^2+x-6}{x(x+3)}$

= $\frac{4x^2+x-6}{x(x+3)}$ → A