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4 years ago

3(-8m - 1) + 5 (m + 8)

Mathematics

1 answer:

Vlada [557]4 years ago

7 0

Step-by-step explanation:

3(-8m-1) + 5(m+8) (remove the parentheses)

-24m - 3 + 5m + 40 (collect like terms and calculate)

-19m + 37

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The given table and equation represent the cost for carnival rides.

lozanna [386]

Answer:

The ordered pairs that are presented are (7, 99.5) and (3, 51.5)

Step-by-step explanation:

We are given the cost function of the carnival rides as

$c=15.5+12f$

which is a typical linear expression of the form $y=ax+b$ where here $y=c$ , $f=x$ , $a=12$ and $b=15.5$ . To check if an ordered pair i.e. a point $(x,y)$ , is represented by the table we can simply plug in the equivalent $x$ value in the equation, and check if the result matches the $y$ value.

So, lets assume that all points are given correctly and they are as follow:

$A. (7, 99.5)\\B. (75.5, 5)\\C. (3, 51.5)\\D. (123.5, 9)$

Now let us check each point with our function as follow:

Point A

$(7,99.5)\\\\c=15.5+12(7)\\c=15.5+84\\c=99.5$

So point A is part of the equation.

Point B

$(75.5,5)\\c=15.5+12(75.5)\\c=15.5+906\\c=921.5$

So point B is NOT part of the equation.

Point C

$(3,51.5)\\c=15.5+12(3)\\c=15.5+36\\c=51.5$

So point C is part of the equation.

Point D

$(123.5,9)\\c=15.5+12(123.5)\\c=15.5+1482\\c=1497.5$

So point D is NOT part of the equation.

8 0

4 years ago

Read 2 more answers

GEOMETRY TWO EASY QUESTIONS PELASE HELP

Strike441 [17]

10)
6y - 16 = 4y + 6
2y = 22
y = 11

11)
2x + 5x + 5 = 180
7x + 5 = 180
7x = 175
x = 25

6 0

3 years ago

Read 2 more answers

At a concession stand, three hot dogs and 4 hamburgers cost $11.50; 4 hot dogs and three hamburgers cost $11.25 Find the cost

Alekssandra [29.7K]

Answer:11.50/4=2.87

2.87×3=8.61

11.25-8.61=2.62

one hamburger$ 2.87

one hot dog $2.64

Step-by-step explanation:

7 0

3 years ago

Simplify by rationalizing the denominator. 15√2 / √270

ladessa [460]

$\frac{ \sqrt{15} }{3}$ ✅

Step-by-step explanation:

$\frac{15 \sqrt{2} }{ \sqrt{270} } \\ \\ = \frac{15 \sqrt{2} }{ \sqrt{270} } \times \frac{ \sqrt{270} }{ \sqrt{270} } \\ \\= \frac{15 \sqrt{2} \times \sqrt{270} }{270} \\\\ (∵ \sqrt{a} \times \sqrt{a} = a) \\\\ = \frac{15 \sqrt{540} }{270} \\ \\= \frac{ \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 5} }{18} \\ \\ = \frac{ \sqrt{ {2}^{2} \times {3}^{2} \times 15 } }{18} \\ = \frac{2 \times 3 \sqrt{15} }{18} \\ \\ = \frac{6 \sqrt{15} }{18} \\ \\ = \frac{ \sqrt{15} }{3}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}$

7 0

3 years ago

Read 2 more answers

What addition doubles fact can help you find 4+3? explain

adell [148]

U can. Do 3+4 u just switch the number

6 0

4 years ago