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natali 33 [55]
3 years ago
13

An apple is falling from a tree. Disregarding air resistance, which diagram shows the free-body diagram of the force or forces a

cting on the apple?
Physics
3 answers:
inysia [295]3 years ago
7 0
No diagram is shown. None of the above.
gladu [14]3 years ago
7 0
I believe its none of the above atleast show a pic! Or diagram
Jeff 3 years ago
0 0

It’s the second one the downward arrow with Fg

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An object is dropped from rest from a 70.6 m tower. Air resistance is negligible. After 0.32 seconds, what is magnitude and dire
dem82 [27]

Answer:

<em>1,378.9ms²</em>

Explanation:

Given the following

Distance S = 70.6m

Time t = 0.32secs

Initial velocity = 0m/s

Required

Acceleration

Using the equation of motion

S = ut+1/2at²

Substitute

70.6 = 0+1/2a(0.32)²

70.6 = 0.0512a

a = 70.6/0.0512

a = 1,378.9

<em>Hence the acceleration is 1,378.9ms²</em>

7 0
3 years ago
In January 2006, astronomers reported the discovery of a planet comparable in size to the earth orbiting another star and having
Orlov [11]

Answer:

R = 5.28  103 km

Explanation:

The definition of density is

              ρ = m / V

              V = m /ρ

Where m is the mass and V the volume of the body

The volume of a sphere is

            V = 4/3 π r³

Let's replace

             4/3 π r³ = m / ρ

             R =∛ ¾ m / ρ π

The mass of the planet is

              M = 5.5 Me

              R = ∛ ¾ 5.5 Me /ρ π

Let's reduce the density to SI units

             ρ = 1.76 g / cm³ (1 kg / 10³ g) (10² cm / 1 m)³

             ρ = 1.76 10³ kg / m³

Let's calculate

               R = ∛ ¾ 5.5 5.97 10²⁴ / (1.76 10³ pi)

               R = ∛ 0.14723 10²¹

               R = 0.528 10⁷ m

               R = 0.528 104 km

               R = 5.28  103 km

8 0
4 years ago
A rocket powered sled accelerates a jet pilot in training straight forward from rest to 270 km/h in 12.1 seconds. Find:
Ilia_Sergeevich [38]

Answer:

  1. 6.198 m/s²
  2. 4.48 s
  3. 453.77 m

Explanation:

5 0
3 years ago
An electron moves with a speed of 8.0×106m/s along the -z-axis. It enters a region where there is a uniform magnetic field B = (
Crazy boy [7]

Answer:

Acceleration, a=9.36\times 10^{18}\ m/s^2

Explanation:

It is given that,

Speed of electron, v=8\times 10^6\ m/s

Charge on an electron, q=1.6\times 10^{-19}\ C

Mass of electron, m=9.1\times 10^{-31}\ kg

Magnetic field, B=5.5i-3.7j

Magnitude, |B|=\sqrt{5.5^2+(-3.77)^2}=6.66\ T

Magnetic force is given by :

F=qvB

Also, F = ma

a=\dfrac{qvB}{m}

a=\dfrac{1.6\times 10^{-19}\times 8\times 10^6\times 6.66}{9.1\times 10^{-31}}

a=9.36\times 10^{18}\ m/s^2

So, the acceleration of the electron is 9.36\times 10^{18}\ m/s^2. Hence, this is the required solution.

5 0
3 years ago
What is the total charge of barium oxide?
vichka [17]
Barium cation has +2 charge and oxide anion has −2 charge
3 0
3 years ago
Read 2 more answers
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