Determine the number of ways to throw two die and get the number 11, as well as the probability of getting 11.
1 answer:
Answer:
1/18
Explanation:
The number of ways in which two die can be thrown is the sample space of the experiment
(1,1), (1,2) (1,3), (1,4) (1,5) (1,6)
(2,1), (2,2) (2,3), (2,4) (2,5) (2,6)
(3,1), (3,2) (3,3), (3,4) (3,5) (3,6)
(4,1), (4,2) (4,3), (4,4) (4,5) (4,6)
(5,1), (5,2) (5,3), (5,4) (5,5) (5,6)
(6,1), (6,2) (6,3), (6,4) (6,5) (6,6)
From here it can be seen that there are only two cases where the sum on the two die is 11 i.e., (6,5) and (5,6)
∴ Probability of getting 11 is<u> 1/18</u>
You might be interested in
Answer:
New force,
Explanation:
It is given that,
Force acting between two charged particles,
We need to find the force if they are moved so they are only one-eighth as far apart.
The force between two charged particles separated at a distance of r is given by :
............(1)
If the charges are one-eighth as far apart then, r' =(1/8)r and new force is given by :
..........(2)
Dividing equation (1) and (2) :
F' = 48000 N
or
Hence, this is the required solution.
Answer:
M₀ = 5i - 4j - k
Explanation:
Using the cross product method, the moment vector(M₀) of a force (F) is about a given point is equal to cross product of the vector A from the point (r) to anywhere on the line of action of the force itself. i.e
M₀ = r x F
From the question,
r = i + j + k
F = 1i + 0j + 5k
Therefore,
M₀ = (i + j + k) x (1i + 0j + 5k)
M₀ =
M₀ = i(5 - 0) -j(5 - 1) + k(0 - 1)
M₀ = i(5) - j(4) + k(-1)
M₀ = 5i - 4j - k
Therefore, the moment about the origin O of the force F is
M₀ = 5i - 4j - k