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madam [21]
4 years ago
7

If an object is at rest would there be any forces acting upon it?

Physics
2 answers:
Marat540 [252]4 years ago
7 0
Yes gravity would be the force that is holding that object down
ValentinkaMS [17]4 years ago
3 0
Well, it seems as though there would be no forces, because it's "at rest", but wouldn't gravity still be acting upon it?
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How can you convert a temperature expressed in degrees celsius to kelvin?
ozzi
By subtracting the value of absolute zero, also know as adding 273.15!
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The table shows the potential energy and kinetic energy of a skier at two different positions on a hill.
Serggg [28]

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30,000 units, because total energy remains unchanged

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3 years ago
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A disk, initially rotating at 120 rpm, is slowed down with a constant acceleration of magnitude 4 rad s2. If the disk has diamet
andrey2020 [161]

Answer:

Explanation:

given,

ω₁ = 120 rpm

        1 rpm = \dfrac{2\pi }{60} rad/s

         \omega_1 =120\times \dfrac{2\pi }{60} rad/s

                          = 12.56 rad/s

α = - 4 rad/s²

diameter of disk = 20 cm

final angular velocity = 0

t = \dfrac{\omega_f-\omega_i}{\alpha}

t = \dfrac{0-(12.56)}{-4}

t = 3.14 s.

2) \theta = \omega_i t +\dfrac{1}{2} \alpha t^2

              =  12.56\times 3.14 +\dfrac{1}{2}\times (-4)\times 3.14^2

              = 19. 72 radians

3) total angular distance rotated

x = θ R

x = 19.72 × 0.1 = 1.97 m

x = 2 m

3 0
3 years ago
calculate the gravitational force in between two objects of mass 25 kg and 20 kg if distance between them is 5m ​
sladkih [1.3K]

Answer:

<em><u>Gravitational</u></em><em><u> </u></em><em><u>force</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>1</u></em><em><u>.</u></em><em><u>3</u></em><em><u>3</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em><em><u>^</u></em><em><u>-</u></em><em><u>9</u></em><em><u> </u></em><em><u>N</u></em>

Explanation:

force =  \frac{GMm}{ {r}^{2} }

{ \sf{ =  \frac{6.67 \times  {10}^{ - 11} \times 25 \times 20 }{ {5}^{2} } }} \\  \\  = { \sf{1.33 \times  {10}^{ - 9} \: newtons }}

5 0
3 years ago
PLS HELP. I WILL MARK U THE BRAINLIEST IF U ANSWER EVERYTHING STEP BY STEP AND CORRECTLY.
dsp73

distance is the length of his trip so 15( 3+4+8)

displacement is how far he is from his original point ( -5)( -4^2 + 3^2 = 5^2) he was displaced 5 meters from his start position

3 0
3 years ago
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