Answer: non-linear 40 1/2 Step-by-step explanation: This is a non-linear function specifically it is an oscillating function The initial position of the weight occurs at t=0 and from the graph we see that at t=0, the weight position is 40 centimeters The weight is said to reach equilibrium when its position is at 0 cm. From the graph we can see that the function first reaches 0 cm at t=0.5 seconds or at t= 1/2 second
12-9=3
3+12+4,5=19,5
19 hours and 30 min
Answer:
10.8 gallons
Step-by-step explanation:
First change everything to inches:
2.75 ft = 33 in
1.5 ft = 18 in
Volume of tank = lwh = (33)(18)(7) = 4158 in³
The tank is 40% full, so only 60% is need to fill it. To find 60%, multiply 4158 by 0.6 = 2494.8 in³
Now find out how much 2494.8 in³ is in gallons:
231 in³ = 1 gallon
1 in³ = 1/231 gallons
2494.8 = (1/231)(2494.8) gallons = 10.8 gallons
Answer:
c = 12
Step-by-step explanation:
3(c - 4) = 4(c - 6)
Use the distributive property on each side.
3c - 12 = 4c - 24
Now you need the terms with c on the left side and the numbers on the right side. Subtract 4c from both sides. Add 12 to both sides.
3c - 4c - 12 + 12 = 4c - 4c - 24 + 12
Combine like terms on each side.
-c = -12
Multiply both sides by -1.
c = 12
Answer:
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- <u>No. You would have to cut the number of veggie burgers in more than half.</u>
Explanation:
<u>1. Model the situation with a system of equations</u>
<u />
<u>a) Name the variables:</u>
- number of turkey burgers: t
- number of veggie burgers: v
<u />
<u>b) Number of burgers:</u>
<u />
<u>c) Cost of the 50 burgers:</u>
<u>2. Solve that system of equations:</u>
<u />
<u>a) System</u>
<u>b) Mutliply the first equation by 2 and subtract the second equation</u>
- 100 = 2t + 2v
- 90 = 2t + 1.50v
- v = 20 ⇒ t = 50 - 20 = 30
<u />
<u>c) How much would you spend if the next year you buy the double of 20 turkey burgers (40) and the half of 30 veggie burgers (15)</u>
- $2(40) + $1.50(15) = $80 + $22.50 = $102.50
Then, you if you double the number of turkey burgers, and cut the number burgers in half, you would spend more than $90 ($102.50).
