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3 years ago

True or false?

Mathematics

1 answer:

Firdavs [7]3 years ago

8 0

Answer:

Step-by-step explanation:

brainliest pls

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WILL MARK BRAINLIEST '<br> IF YOU DONT KNOW DONT ANSWER

Soloha48 [4]

Answer: A) Alternate Exterior

Step-by-step explanation:

Let's find out the defenition of alternate exterior; "If a pair of parallel lines are cut by a transversal line, then the alternate exterior angles are congruent".

I hope this helps!

8 0

3 years ago

-1/4b + 1/2 = 5/6<br>Find b

QveST [7]

Answer:

b = -4/3

Step-by-step explanation:

First, subtract the 1/2 over

-1/4b+1/2=5/6

5/6-1/2

To get a common denominator of 6, multipy 1/2 by 3

5/6-1/2(3)

5/6-3/6=2/6

-1/4b=2/6

Next, multiply by the reciprocal of -1/4, or -4

(-4)-1/4b=2/6(-4)

b=-4/3

7 0

3 years ago

The radius of the base of a cylinder is 28 cm and its height is 48 cm. Find the surface

Furkat [3]

Answer:

D) $4256\pi\:\text{cm}^2$

Step-by-step explanation:

$SA=2\pi r h+2\pi r^2\\\\SA=2\pi(28)(48)+2\pi(28)^2\\\\SA=2\pi(1344)+2\pi(784)\\\\SA=2688\pi+1568\pi\\\\SA=4256\pi\:\text{cm}^2$

7 0

2 years ago

Read 2 more answers

Find missing angles

Rainbow [258]

Answer:3=37 m1=62 m2=45 m3=24

Step-by-step explanation:

7 0

3 years ago

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

4 0

3 years ago