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igor_vitrenko [27]
3 years ago
6

Laura is now trying to come up with a number where three less than 8 times the number is equal to half of 16 times the umber aft

er it was increased by 1
Mathematics
1 answer:
ELEN [110]3 years ago
4 0
8n-3=1/2(16n+1)
is the equation i come up with which would have no solutions.
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Find the exact angular velocity in radians per hour wind W= 4.1 rpm
nataly862011 [7]

Answer:

1545.66 rad/h

Step-by-step explanation:

We need to find the angular velocity in rad/hour when wind is moving with a speed of 4.1 rpm.

We know that,

1 revolution = 2π rad

1 hour = 60 minute

So,

4.1\ rmm = 4.1\times \dfrac{2\pi }{(\dfrac{1}{60})}\ rad/h\\\\=1545.66\ rad/h

So, the required angular velocity is 1545.66 rad/h.

6 0
3 years ago
What was haley’s function in standard form
Stels [109]

Answer: 7,-10,-2

Step-by-step explanation:

3 0
3 years ago
If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
The bearing of a plane from an airport is 65 degrees
AleksAgata [21]

Answer:

115

idk how to explain this but u just use the protractor

8 0
3 years ago
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if I had a thousand candies and divide them by 5 then added 20 then took away 1 then multiple by 10 what would my answer be.
Goryan [66]
Your answer would be 210 candies
3 0
3 years ago
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