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2 years ago

How to solve for the shaded region

Mathematics

1 answer:

k0ka [10]2 years ago

5 0

The shaded region is a triangle. Triangle area can be determined with formula
a = 1/2 × b × h

From the question, we know that the triangle consists of
base = 10 - 6 = 4 m
and the height is the dimension which is perpendicular to the base,
height = 6 m

Find the triangle area
a = 1/2 × b × h
a = 1/2 × 4 × 6
a = 1/2 × 24
a = 12

The area of the shaded region is 12 m²

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2 years ago

Joan has 294 black marbles. Joan has 42 times more black marbles than Dan. How many black marbles does Joan has?

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3 years ago

20 points helppppp which pair shows equivilent fractions

skelet666 [1.2K]

Answer:

Third

Step-by-step explanation:

First would be, simplified, 2x+10=2x-10

Second, simplified, -2x-10=2x-10

Third, simplified, -2x-10=-2x-10

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So it's third :)

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4 0

2 years ago

Read 2 more answers

OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

3 0

2 years ago

In the following figure, triangle ABC and triangle DEF are similar. What is the value of x ? Triangle ABC and triangle DEF are s

Shtirlitz [24]

X = 25.5 mm.

Using the similarity statement given, that ΔABC ~ ΔDEF, we set up a proportion:

8.5/x = 4/12

Cross multiply:
4*x = 8.5*12
4x = 102

Divide both sides by 4:
4x/4 = 102/4
x = 25.5

7 0

2 years ago