Answer:
Therefore the maximum number of video games that we can purchase
is 6.
Step-by-step explanation:
i) Let us say the number of video game system we can buy that costs $185
is x and the number of video games of cost $14.95 is y.
ii) The total amount we can spend on the purchase of the video game
system is $280.
iii) Now with the amount of $280 mentioned in ii) we can see that the
number of game systems that can be bought is 1.
Therefore x = 1.
Therefore the equation we can write to equate the number of video
games and video game system is given by $185 + $14.95 × y ≤ 280
Therefore 14.95 × y ≤ 280 - 185 = 95
Therefore y ≤ 95 ÷ 14.95 = 6.355
Therefore the maximum number of video games that we can purchase
is 6.
Answer: ok so Let's simplify step-by-step.
r−3q+5p−(−4r−3q−8p)
Distribute the Negative Sign:
=r−3q+5p+−1(−4r−3q−8p)
=r+−3q+5p+−1(−4r)+−1(−3q)+−1(−8p)
=r+−3q+5p+4r+3q+8p
Combine Like Terms:
=r+−3q+5p+4r+3q+8p
=(5p+8p)+(−3q+3q)+(r+4r)
=13p+5r
Step-by-step explanation:
The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.
Answer:
24
Step-by-step explanation:
