Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
Step-by-step explanation:
Yes because
An equation of a circle:
(x - a)² + (y - b)² = r²
(a; b) - a coordinates of a center
r - a radius
r = 8; (-10; 6) ⇒ a = -10 and b = 6
subtitute
(x - (-10))² + (y - 6)² = 8²
Answer: (x + 10)² + (y - 6)² = 64
Answer:
$1,800.
Step-by-step explanation:
15 x 15 = 225
225 x 8 = 1800
Feel free to let me know if you need more help! :)
Answer:
21.16
Step-by-step explanation:
Starting from the theory we have the following equation:
Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:
solving for "c", knowing that fi is a tabulating value:
therefore the value of c is equal to 21.16
