1.) -4x-32 2.) -6x-3 3.) -3n-28 4.) -2x-7 5.) ??? 6.) 4b-2 (I couldn't figure out #5 sorry)
<span>The median would be preferred over the mean in such scenarios because the median will lessen the impact of the outliers that fall within the "tail" of the skew. Therefore, if a curve is normally distributed, that is to say that data is normally distributed, there will be two tails, each with approximately equal proportions of outliers. Outliers in this case being more extreme numbers, and are based on your determination depending on how you are using the data. If data is skewed there is one tail, and therefore it may be an inaccurate measure of central tendency if you use the mean of the numbers. Thinking of this visually. In positively skewed data where there is a "tail" towards the right and a "peak" towards the left, the median will be placed more in the "peak", whereas the mean will be placed more towards the "tail", making it a poorer measure of central tendency, or the center of the data.</span>
Answer:
He has one.
Step-by-step explanation:
He has five, and gives sarah four. That means that you take all but one away from 5. 5-4=1.
Full question:
A transaction is positive if there is a sale and negative when there is a return. Each time a customer uses credit card for a transaction, the credit company charges Isabel. The credit company charges 1.5% of each sale and a fee of 0.5 % for returns
Let x represent the amount of a transaction and let f(x) represent the amount Isabel is charged for the transaction. Write a function that expresses f(x)
Answer:
f(x)= 0.015(x)
f(x)= 0.005(x)
Explanation:
If Isabel makes a sale, she has a positive transaction and therefore is charged 1.5%(which is 0.015) by the credit company for the transaction. If the product is returned, it is a negative transaction and the credit company charges 0.5%(which is 0.005) for the transaction. The functions for positive and negative transactions would be different as indicated in the answer since transactions( given by x) are different- positive and negative.
