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Soloha48 [4]
3 years ago
7

10 minus 1/3 of a number is 4

Mathematics
1 answer:
weqwewe [10]3 years ago
4 0

Answer:

10-1/3x=4

Step-by-step explanation:

10 minus is 10-

1/3 of a number is 1/3x

is 4 means =4

10-1/3x=4

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Express each of the following in standard form 0.0 0 0 0 0 0 0 0 0 2 2 1​
Anastasy [175]
answer= 2.21 x 10^-10
3 0
3 years ago
For the geometric series given by 5 + 10 + 20+ . . . , which of the following statements is FALSE?
slava [35]

Answer:

All statements are true

Step-by-step explanation:

1. The statement S_{500}>S_{499} is true, because S_{499} is the sum of first 499 terms,  S_{500} is the sum of first 500 terms,  and all these terms are positive, then the sum of smaller number of terms is less than the sum of larger number of terms.

2. The statement S_{500}>a_{500} is true, because S_{500} is the sum of first 500 terms,  a_{500} is 500th term and the sum of 500 terms is greater than the 500th term.

3. The statement S_1=a_1 is true, because S_1 is the sum of first 1 term that is exactly  a_1.

All statements are true.

5 0
3 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
Choose the correct inequality based on the number line below
Kryger [21]

Answer:

D.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How many yards will the players have run ?? Please help
Whitepunk [10]

Answer:

125.3 yards

Step-by-step explanation:

He wants them to run the  so 110^2+60^2 =which is 125.3.

Hope this helps plz mark brainliest :D

8 0
3 years ago
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