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3 years ago

50 PTS PLUS I WILL MARK BRAINLIEST

Mathematics

2 answers:

ch4aika [34]3 years ago

7 0

Subtract 5x to both sides

mr Goodwill [35]3 years ago

5 0

Answer:

add 10y to both sides of the equation

Step-by-step explanation:

5x-10y=30

+10y +10y

5x=10y+30

/5 /5 /5

x=2y+6

You might be interested in

Find the constant of proportionality for the table of values.

Anna [14]

The constant of proportionality k is 3.5

Step-by-step explanation:

Proportionality describes any relationship that is always in the same

ratio

If two quantities x and y are in proportionality, then

1. y ∝ x

2. y = k x , where k is the constant of proportionality

∵ x ⇒ 6 , 7 , 8 , 9

∵ y ⇒ 21 , 24.5 , 28 , 31.5

∵ y ∝ x

∴ y = k x

- Use x = 6 and y = 21 to find the value of k

∵ x = 6 and y = 21

∴ 21 = k (6)

- Divide both sides by 6

∴ k = 3.5

- Use x = 7 and y = 24.5 to find the value of k

∵ x = 7 and y = 24.5

∴ 24.5 = k (7)

- Divide both sides by 7

∴ k = 3.5

- Use x = 8 and y = 28 to find the value of k

∵ x = 8 and y = 28

∴ 28 = k (8)

- Divide both sides by 8

∴ k = 3.5

- Use x = 9 and y = 31.5 to find the value of k

∵ x = 9 and y = 31.5

∴ 31.5 = k (9)

- Divide both sides by 9

∴ k = 3.5

The constant of proportionality k is 3.5

Learn more:

You can learn more about proportionality in brainly.com/question/10708697

#LearnwithBrainly

4 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$