The co ordinates of P' is (-7,-2) and Q' is (-16, -8)
<u><em>Explanation</em></u>
PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.
According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)
When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>
Suppose, the co ordinate of Q' is (x, y)
Now according to the mid-point formula, the coordinate of P or P' will be: , which is actually at (-7, -2)
Thus.....
So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)
Answer:
4x-8>-4
Step-by-step explanation:
2-(2x-4)>-4
2- times (2x) = 4x
2- times (-4) = -8
answer is
4x-8>-4
The area of a triangle can be calculated using the following equation:
A = 1/2 (B x H)
Where B is the dimension of the base and H is the height of the triangle.
Since the area is known and the dimension of the base is also known, substitute the values into the equation to find the height:
3.6 cm2 = 1/2 (6 cm) (H)
Solving yields an answer of 1.2 cm. Hence the height is 1.2 cm.
Add 5 to 19 which is 24 then divide it by -6 and it’s x= -4
I need help on this one as well