All categories

4 years ago

Write this number in expanded form 20,484,163

Mathematics

2 answers:

viva [34]4 years ago

8 0

Twenty million, four hundred and eighty four thousand, one hundred and sixty three.

svetoff [14.1K]4 years ago

7 0

(2·10,000,000) +(4·100,000)+(8·10,000)+(4·1000)+(1·100)+(6.10)+(3·1)
the dots nean multiply

You might be interested in

Of the

k0ka [10]

Answer:

add a peireiod

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?

Keith_Richards [23]

Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6

Using (i)

$BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7$

Now , AE = 4(7)-6 = 28-6 = 22

AC =2 AE = 2 (22) =44 units.

Hence, x=7 and AC = 44 unuts.

3 0

3 years ago

Find the 20th term in the sequence, where the first term is -2 and the common ratio is-2.

geniusboy [140]

Answer:

Step-by-step explanation:

(1)

a1=-2

r=-2

$a_{20}=(-2)(-2)^{20-1}=-2(-2)^{19}=2^{20}=1048576\\(2)\\a_{1}=1000\\r=\frac{200}{1000} =\frac{1}{5} \\a_{8}=1000(\frac{1}{5} )^{8-1}=1000(.2)^7=0.0128\\(3)\\a_{1}=2\\a_{3}=50\\a_{2}=\sqrt{2*50} =10\\r=\frac{10}{2} =5$

6 0

3 years ago

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$