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mezya [45]
3 years ago
9

What is the probability that a randomly selected child from this group will have red hair, given that he has straight hair? (Ent

er your answer as a fraction.)
Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

Your question was incomplete, as the values are not given.

I guess these are the values you are talking about.

Hair Type   Brown   Blond   Black    Red    Totals

Wavy           20           5          15         3        43

Straight        80          15         65        12       172

Totals          100         20         80        15       215

Now w have to find out the probability of a child with red, straight hair.

Total no of children with straight hair are = 172

The children having straight red hair = 12

The probability of selected child = 12/172.

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A box is 12 cm wide 12 cm long and 15 cm tall what is the total surface area of 4 such boxes
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Surface area = 2(12*12+15*12+15*12) = 1008

1008 * 4 = 4032
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3 years ago
Pls help A bag contains 40 colored tiles. There are 12 red, 17 blue, 8 yellow and 3 green. One tile is drawn at
aleksley [76]
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2 years ago
Given that f(x)=6x+2 and g(x)=2x+4/5 solve for g(f(1))<br><br> A.1<br> B.3<br> C.4<br> D.8
GrogVix [38]

Answer:

The value of g(f(1)) is 84/5

Step-by-step explanation:

To find the answer to a composite function, start with the function on the inside, which is f(1). So, we input 1 into the f(x) equation and evaluate.

f(x) = 6x + 2

f(1) = 6(1) + 2

f(1) = 6 + 2

f(1) = 8

Now that we have the answer of 8, we can input that in for x in the outside function, which is g(x).

g(x) = 2x + 4/5

g(8) = 2(8) + 4/5

g(8) = 16 + 4/5

g(8) = 84/5

6 0
2 years ago
Which 3 values would make this inequality true? 48 &lt; 6n
tekilochka [14]

Answer:

The three values are: 9, 10 and 11

5 0
2 years ago
Question regarding limits to see if my procedure of getting the answer is right!!!!
Licemer1 [7]
\displaystyle\lim_{x\to0}\frac{\tan x^2}x=\lim_{x\to0}x\frac{\tan x^2}{x^2}=\lim_{x\to0}\frac x{\cos x^2}\times\lim_{x\to0}\frac{\sin x^2}{x^2}

Recall that

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

and so replacing x with x^2, you get that the second limit is 1. Meanwhile,

\displaystyle\lim_{x\to0}\dfrac x{\cos x^2}=\dfrac01=0

so the limit is 0.
7 0
2 years ago
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