Answer:
0.6210
Step-by-step explanation:
Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries
Sample size n =87
Sample proportion will follow a normal distribution with p =0.39
and standard error = 
the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
=
There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
Answer:
Don't know the exact equation but trying to explain
X is what the stuff that problem saying. Let's say you have books from library and you're returning them late you will pay $30 dollars for each of them
6x+1 / 2x +6 - 5/2
Factor 2 out of the denominator of the first fraction:
6x+1 / 2(x+3) - 5/2
Rewrite 5/2 to have a common denominator with the first fraction:
6x+1/2(x+3) - 5(x+3) / 2(x+3)
Simplify terms:
6x +1 - 5(x+3) / 2(x+3)
Use distributive property:
6x +1 - 5x -15 / 2(x+3)
Combine like terms for final answer:
(x-14) / 2(x+3)
Well first you multiply 5 times 3 which is 15 then you add 4 which is 19 and 19 times 3 is 57 57-5 is 52
Answer:
Hello,
Answer A : 11.2 ≤ X ≤ 29.2
Step-by-step explanation:
