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Lorico [155]
3 years ago
15

A car seller buys a car from a manufacturer for $10,000. He increases the cost by 5 percent. What is the markup amount?

Mathematics
1 answer:
torisob [31]3 years ago
3 0
We know that:

The markup is the price added to the cost price of goods...

To find the markup, we must multiply the percent increase by the original price (before markup).

So:

10,000 x 5% (or 0.05) = ?

10,000 (You do not have to follow my way of multiplying, do what is comfortable for u)
x       5 (Ignore the decimals then we move it after we get the answer) 
----------
50,000 move the decimal back 2 places so it is 500

The final answer is:

The markup amount is $500...




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Step-by-step explanation:

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B’(9,6)

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Y=x+2 2x-y=-4 Solve the systems of equations
larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

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Substitute equation 1 into equation 2

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2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

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Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?
Tema [17]

Answer:

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Step-by-step explanation:

We are given that

f(x)=tan(x)-\frac{2}{x}

g(x)=x^2+8

We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

g(y)=y^2+8

Now,

f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)

f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

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-4 = 3/4 * 5 + b
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So y = 3/4x - 31/4
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