How does the volume of a cylinder change when its diameter is halved? Explain Please.
1 answer:
The answer is: it will decrease 4 times. Let d be diameter and h height of a cylinder The volume of a cylinder is: V1 = π * (d/2)² * h = π * d²/4 * h = π * d² * h / 4 If diameter is halved, the volume is: V2 = π * ((d/2)/2)² * h = π * (d/4)² * h = π * d²/16 * h = π * d² * h / 16 Now, let's compare them: V1 / V2 = (π * d² * h / 4) / (π * d² * h / 16) π * d² * h can be cancelled out: V1 / V2 = (1/4) / (1/16) = (1/4) * 16 = 16/4 = 4 Therefore, the volume of the smaller cylinder will decrease 4 times.
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