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3 years ago

How does the volume of a cylinder change when its diameter is halved? Explain Please.

1 answer:

8 0

The answer is: it will decrease 4 times.

Let d be diameter and h height of a cylinder

The volume of a cylinder is:
V1 = π * (d/2)² * h = π * d²/4 * h = π * d² * h / 4
If diameter is halved, the volume is:
V2 = π * ((d/2)/2)² * h = π * (d/4)² * h = π * d²/16 * h = π * d² * h / 16

Now, let's compare them:
V1 / V2 = (π * d² * h / 4) / (π * d² * h / 16)

π * d² * h can be cancelled out:
V1 / V2 = (1/4) / (1/16) = (1/4) * 16 = 16/4 = 4

Therefore, the volume of the smaller cylinder will decrease 4 times.

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A number with 2 decimal places, that is bigger than 4 1/5 but smaller than 4.25

LUCKY_DIMON [66]

Answer:

4.21, 4.22, 4.23,

4.24 (choose any one)

Step-by-step explanation:

since 4 1/5 is 4.20, so the numbers in between 4.20 and 4.25 are 4.21, 4.22, 4.23,

4.24 (choose any one)

3 0

3 years ago

A number is divisible by 3 if the sum of the digits is divisible by 3 true or false

shtirl [24]

ANSWER:
It is true as the divisibility rule of three says -
WE HAVE TO ADD ALL THE DIGITS OF THE NUMBER AND IF THAT SUM IS DIVISIBLE BY THREE THEN THE PARTICULAR NUMBER IS DIVISIBLE BY THREE.
EXAMPLE 2+7=9 and 3*3=9
HOPE IT HELPS!!!!
PLEASE MARK BRAINLIEST!!!!

8 0

3 years ago

Two fewer than a number doubled is the same as the number decreased by 38. if n is "the number," which equation could be used to

Alona [7]

$\displaystyle \\ 
\text{We use the following equation:} \\ \\ 
 \frac{n}{2} = n - 38 \\ \\ 
We solve for n: \\ \\ 
 \frac{n}{2} = n - 38 ~~\Big| \times 2 \\ \\ 
n = 2 \times n - 2 \times 38 \\ \\ 
n = 2n - 76 \\ \\ 
2n - n = 76 \\ \\ 
\boxed{n = 76} \\ \\ 
\text{Verification: } \\ \\ 
\frac{n}{2} = n - 38 \\ \\ 
\frac{76}{2} = 76 - 38 \\ \\ 
\boxed{38 = 38 ~~~ Correct }$

8 0

4 years ago

Find the distance from Q: (5.7 , 2.6) to R: (-3, 5.9)

Firdavs [7]

It would be around 9.304. so you'd round to the nearest tenth 9.3

6 0

3 years ago

Read 2 more answers

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: