2/(11/16 +3) I know the answer is 12/29. I just don't know how to get there

Based o the sample results what percent of the opulation prefers reading a hard copy i fht e digital copy is 4, the hard copy is

Lisa [10]

Based on the sample results of the population the percentage of population that prefers reading a hard copy i fht e digital copy is 4, the hard copy is 21 and n equas 25 is 84%

Step-by-step explanation:

From the above question we know that .

Total number of population, n = 25

Number of people who prefer to read a digital copy = 4

Number of people who prefer to read a hard copy = 21

As per the question we need to find out the percentage of population who prefer to read hard copy.

So we use the formula

Percent of population preferring hard copy = Hard copy/Total*100

Percent of population that prefers hard copy = 21/25*100

Percent of population that prefers hard copy = 0.84 × 100 = 84%

So , the percent of population who prefers to read a hard copy are about 84%.

3 0

3 years ago

On a standard reticulocyte preparation with new methylene blue, there are 100 cells counted with blue-stained granulofilamentous

DIA [1.3K]

Answer:

0.322 × 10¹² /L

Step-by-step explanation:

Data provided in the question:

Number of cells counted with blue-stained granulofilamentous material

i.e number of RET = 100

The red blood cells count = 3.22 × 10¹² /L

Hematocrit = 30%

Now,

RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%

= [ 100 ÷ 1000 ] × 100%

= 0.1 × 100%

= 10%

also,

Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100

= [ 10 × 3.22 × 10¹² /L ] ÷ 100

= 0.322 × 10¹² /L

8 0

3 years ago

(-2,3)(0,8) what is en equation for these points

jenyasd209 [6]

Answer:

The line equation that passes through the given points is 5x – 2y + 16 = 0

Explanation:

Given:

Two points are A(-2, 3) and B(0, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

$\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}$

${(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)$ .............(1)

here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.

Now substitute the values in (1)

$y-8 = \frac{(3-8)}{(- 2 - 0)}\times(x- 0)$

$y-8 = \frac{(- 5)}{(-2)}\times(x)$

$y-8 =\frac{5}{2}x$

2y – 16 = 5x

5x – 2y + 16 = 0

Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.

4 0

3 years ago

Find the sum of the arithmetic series........... 3 + 5 + 7 + 9 + 11 + for 100 terms.

tatyana61 [14]

Answer:

Step-by-step explanation:

3 + 5 +7 +9 + 11 + ....

n = 100

a = 3

d = 5 - 3 = 2

$S_{n}=\frac{n}{2}(2a + (n-1)d)\\\\S_{100}=\frac{100}{2}(2*3+99*2)\\\\=50*(6+198)\\\\= 50 * 204\\= 10200\\$

4 0

3 years ago

Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to do its route and bus B takes 35 minutes to complete its r

DaniilM [7]

Answer:

8:30 pm

Step-by-step explanation:

step 1

Decompose the numbers in prime factors

$30=(2)(3)(5)\\35=(5)(7)$

step 2

Find the LCM

The LCM of 30 min and 35 minutes will be given as

$LCM=(2)(3)(5)(7)=210\ min$

step 3

Adds 210 minutes to the starting time

First, converting 210 minutes to hours

Remember that

$1\ h=60\ min$

will need dividing 210 by 60

$210/60=3.5\ h$

therefore

5:00 pm+3.5 h=8:30 pm

7 0

3 years ago