Answer:
Given: The following system:
4x + y − 2z=18          ......[1]
2x-3y+3z = 21          ......[2]
x-3y=6                      ......[3]
we can write equation [3] as;
3y = x-6                     ......[4]
Multiply by 3 in equation [1] to both sides of an equation we get,
 or
 or 
12x+3y-6z=54              ......[5]
Substituting the equation [4] in [2] and [5] we get;
2x-(x-6)+3z=21 or
2x-x+6+3z=21 
Simplify:
x+3z=15            .....[6]                       [combine like terms]
12x+x-6-6z =54 
Simplify:
13x-6z=60         ......[7]        [Combine like terms]
On Solving equation [6] and [7] simultaneously, 
x+3z=15 
13x-6z=60 
we get the value of x
i.e, x=6
Substitute the value of x in equation x+3z=15  we get
6+3z=15 or
3z=9
Simplify:
z=3
Also, substitute the value of x=6 in equation [3] we get the value of y;
x-3y=6 
6-3y=6 or
-3y = 0
Simplify:
y = 0
Therefore, the solution to the system of three linear equation is, (6, 0 , 3)
 
        
             
        
        
        
 Answer:$825. 00
Add $25.+50. For week 1 then add $25.each additional week for 6weeks.
Step-by-step explanation:
 
        
             
        
        
        
8/10*8/21
= 64/210
= 32/105