Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Answer:
it's being divided by -5
Step-by-step explanation:
-5m= -40
m=8
The answer will stay the same because you can't combine like terms.
Also I don't think it is Order of Ops because it doesn't have any exponets, etc.
~JZ
Hope it helps
To find how long it would take him, one has to divide 400 by 160 and then multiply 5 by what that number is. You multiply 5 by the quotient because that is the number that would make it proportional. 400/160 x 5 is 12.5, meaning that the answer is 12.5 minutes, or A.
Umbilical
point.
An
umbilic point, likewise called just an umbilic, is a point on a surface at
which the arch is the same toward any path.
In
the differential geometry of surfaces in three measurements, umbilics or
umbilical focuses are focuses on a surface that are locally round. At such
focuses the ordinary ebbs and flows every which way are equivalent,
consequently, both primary ebbs and flows are equivalent, and each digression
vector is a chief heading. The name "umbilic" originates from the
Latin umbilicus - navel.
<span>Umbilic
focuses for the most part happen as confined focuses in the circular area of
the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces
with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an
outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two
umbilics.</span>
