Answer:
40 miles
Step-by-step explanation:
10X4
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).




Subtract 160 from both sides.

Divide by –20, we get

f = 2.50
Substitute f = 2.5 in equation (3), we get


b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
First, square both sides. This will cancel out the radical.

(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
The first answer to your question is 5 6/10 because you pronounce the decimal as six tenths. There is a simpler form of 5 6/10, it is 5 3/5. This is because you divide six by 2 and get 3 and divide 10 by two and get 5.