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alexdok [17]
2 years ago
8

Please help +25 points

Mathematics
1 answer:
mestny [16]2 years ago
8 0
The answer is D.
Hope I helped
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Please help me id you want BRIANLEIST!!! :)) ty!!!
Bad White [126]

Answer:

5/3

Step-by-step explanation:

4 × x = (6×3+2)/3

---> 4x = 20/3

----> x = 20/12

----> x=5/3

Hope it helps

7 0
2 years ago
Read 2 more answers
the sum of three consecutive integers is three times the second integer. show that this is true for the three consecutive intege
sdas [7]

Step-by-step explanation:

7+8+9=24

second integer is 8 so 8*3=24

3 0
2 years ago
A gardener is planting two types of trees:
ICE Princess25 [194]

Answer:

After 1 year, both the tress will be of the same height.

Step-by-step explanation:

Let us assume in x years, both trees  have same height.

Type A  is 7 feet tall and grows at a rate of 8 inches per year.

⇒The growth of tree A in x years = x times  ( Height growth each year)

                                                        = 8 (x)  = 8 x

⇒Actual height of tree A in x years  = Initial Height + Growth in x years

                                                             = 7 + 8 x

or, the height of tree A after  x years  = 7 + 8x

Type B is 9 feet tall and grows at a rate of 6 inches per year.

⇒The growth of tree B in x years = x times  ( Height growth each year)

                                                        = 6 (x)  = 6 x

⇒Actual height of tree B in x years  = Initial Height + Growth in x years

                                                             = 9 + 6 x

or, the height of tree B after  x years  = 9 + 6x

According to the question:

After x years, Height of tree A  =Height of tree B

⇒7 + 8x   = 9 + 6x

or, 8x - 6x = 9 - 7

or, 2 x  = 2

or, x  =  2/2  = 1    ⇒ x  = 1

Hence, after 1 year, both the tress will be of the same height.

5 0
2 years ago
3.Not Answered 4.Not Answered 5.Not Answered 6.Not Answered 7.Not Answered 8.Not Answered 9.Not Answered 10.Not Answered 11.Not
tino4ka555 [31]

Answer:

The answer to your question is Dependent Variable.

In a linear regression model, the variable that is being predicted or explained is known as Dependent Variable . It is denoted by y and is often referred to as the response variable

Step-by-step explanation:

I don't really know how to explain sorry.

Brainliest pls! :)

8 0
3 years ago
A metal beam was brought from the outside cold into a machine shop where the temperature was held at 65degreesF. After 5 ​min, t
ivolga24 [154]

Answer:

The beam initial temperature is 5 °F.

Step-by-step explanation:

If T(t) is the temperature of the beam after t minutes, then we know, by Newton’s Law of Cooling, that

T(t)=T_a+(T_0-T_a)e^{-kt}

where T_a is the ambient temperature, T_0 is the initial temperature, t is the time and k is a constant yet to be determined.

The goal is to determine the initial temperature of the beam, which is to say T_0

We know that the ambient temperature is T_a=65, so

T(t)=65+(T_0-65)e^{-kt}

We also know that when t=5 \:min the temperature is T(5)=35 and when t=10 \:min the temperature is T(10)=50 which gives:

T(5)=65+(T_0-65)e^{k5}\\35=65+(T_0-65)e^{-k5}

T(10)=65+(T_0-65)e^{k10}\\50=65+(T_0-65)e^{-k10}

Rearranging,

35=65+(T_0-65)e^{-k5}\\35-65=(T_0-65)e^{-k5}\\-30=(T_0-65)e^{-k5}

50=65+(T_0-65)e^{-k10}\\50-65=(T_0-65)e^{-k10}\\-15=(T_0-65)e^{-k10}

If we divide these two equations we get

\frac{-30}{-15}=\frac{(T_0-65)e^{-k5}}{(T_0-65)e^{-k10}}

\frac{-30}{-15}=\frac{e^{-k5}}{e^{-k10}}\\2=e^{5k}\\\ln \left(2\right)=\ln \left(e^{5k}\right)\\\ln \left(2\right)=5k\ln \left(e\right)\\\ln \left(2\right)=5k\\k=\frac{\ln \left(2\right)}{5}

Now, that we know the value of k we can use it to find the initial temperature of the beam,

35=65+(T_0-65)e^{-(\frac{\ln \left(2\right)}{5})5}\\\\65+\left(T_0-65\right)e^{-\left(\frac{\ln \left(2\right)}{5}\right)\cdot \:5}=35\\\\65+\frac{T_0-65}{e^{\ln \left(2\right)}}=35\\\\\frac{T_0-65}{e^{\ln \left(2\right)}}=-30\\\\\frac{\left(T_0-65\right)e^{\ln \left(2\right)}}{e^{\ln \left(2\right)}}=\left(-30\right)e^{\ln \left(2\right)}\\\\T_0=5

so the beam started out at 5 °F.

6 0
3 years ago
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