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Zarrin [17]
3 years ago
8

What is the mean average diviation

Mathematics
2 answers:
topjm [15]3 years ago
6 0
A mean average deviation is data used from average between the mean and each data value. 
enyata [817]3 years ago
4 0
"The mean absolute deviation of a set of data is the average distance between each data value and the mean. The mean number of contacts stored and the distance each data value is from the mean is shown below. Each data value is represented by an ×."
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How many solutions does the system have? \begin{cases} 3x+y=8 \\\\ 2x+2y=8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 3x+y=8 2x+2y=8 ​ Choose 1
ELEN [110]

Answer:

This system has one solution (x=2 and y=2), then the answer is A.

Step-by-step explanation:

The system of equations is:

3x+y=8 (1)

2x+2y=8 (2)

Let's multiply the first equation by 2 and subtract it to the second equation  

6x-2x+2y-2y=16-8

4x=8  

x=2

Using this value in (1) we can find y.

3(2)+y=8

6+y=8

y=2

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!

3 0
3 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
-2, 10, -50. Find the next two terms of this sequence. Give exact values (not decimal approximations)
lyudmila [28]

250 and - 1250

This is a geometric sequence with common ratio r = - 5

multiply each term by - 5 to obtain the next term

- 50 × - 5 = 250

250 × - 5 = - 1250

the sequence is - 2, 10, - 50, 250, - 1250


8 0
3 years ago
Read 2 more answers
The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 1800 hours and a standard deviation
DedPeter [7]

Answer: 68% of light bulbs last between 1765 hours and 1835 hours.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 1800 hours and the standard deviation is 35 hours.

1 standard deviation = 1 × 35 = 35

1800 - 35 = 1765 hours

1800 + 35 = 1835 hours

Therefore, 68% of light bulbs last between 1765 hours and 1835 hours.

6 0
3 years ago
1 5.2.3 Quiz: Completing the Square
Softa [21]

Answer:

x=5/2 or x=2.5

Step-by-step explanation:

x time 2 + 4x=15

6x=15

2x=15

2x=5

7 0
2 years ago
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