Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
15 1/8 -1 3/5=
15 5/40 -1 24/40=
605/40 - 64/40=
541/40= 13 21/40
Answer:13 21/40
Answer: Option 1
Step-by-step explanation:
See attached image
25.3, reflections do not change the length of something and if it can be mapped on to it they should be the same
Answer:
-9/4
Step-by-step explanation:
A perpendicular slope is on that is the negative reciprocal. current slope=4/9 and the negative recipocal is -9/4.
