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3 years ago

Find the product: 8/19 × 12/20 = ?

Mathematics

1 answer:

Sidana [21]3 years ago

6 0

reduce 12/20 to 3/5

multiply both top numbers and then both bottom numbers

8 x 3 = 24

19 x 5 = 95

so answer is 24/95

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I need this to be solved please!

AleksAgata [21]

Answer:

x=50

Explanation:

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2 years ago

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40 ounces equal less then or greater to 4 lbs

astra-53 [7]

<span>4 lb is BIGGER. There are 16 ozs in a pound, so 40 oz = 2.5 lb, which is less than 40 pounds</span>

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3 years ago

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If 20% of a number p is 10, what is 10% of p?

kobusy [5.1K]

Answer:

Step-by-step explanation:

20% of p = 10

20% = 0.2

Multiply

0.2p = 10

Multiply both sides of the equation by 5

p = 50

Find 10% of p

10% = 0.1

Multiply

0.1(50)

10% of p is 5

Hope this helps :)

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3 years ago

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Use a graph in a (-2π, 2π, π/2) by (-3, 3, 1) viewing rectangle to complete the identity.

yaroslaw [1]

First, notice that:

$2\tan (\frac{x}{2})=2\cdot(\pm\sqrt[]{\frac{1-cosx}{1+\cos x})}$

And in the denominator we have:

$1+\tan ^2(\frac{x}{2})=1+\frac{1-\cos x}{1+\cos x}=\frac{1+cosx+1-\cos x}{1+cosx}=\frac{2}{1+\cos x}$

then, we have on the original expression:

$\begin{gathered} \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}=\frac{2\cdot\pm\sqrt[]{\frac{1-\cos x}{1+cosx}}}{\frac{2}{1+\cos x}}=\frac{2\cdot(\pm\sqrt[]{1-cosx})\cdot(1+\cos x)}{2\cdot(\sqrt[]{1+cosx})} \\ =(\sqrt[]{1-\cos x})\cdot(\sqrt[]{1+\cos x})=\sqrt[]{(1-\cos x)(1+\cos x)} \\ =\sqrt[]{1-\cos^2x}=\sqrt[]{\sin^2x}=\sin x \end{gathered}$

therefore, the identity equals to sinx

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1 year ago

The hypotenuse and one of the legs of a right triangle form an angle that has a cosine of square root 2 over 2 . What is the mea

ziro4ka [17]

To answer this question, you can use the values of the unit circle to figure out the angle measurement. Since the cosine is the x value of the circle, we can see that at 45°<span>, the x value is √2/2.
So the missing angle should be 45°</span>

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3 years ago